Geometry · Foundation · 9 min

Compass & straightedge

A perpendicular bisector can be constructed using only equal compass radii and a straightedge.

WHAT HAPPENS IF…Why must the compass radius exceed half AB?
Interactive exploration
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Connect the picture to the ideaCA=CB=DA=DBCA=CB=DA=DB

Choose a compass radius greater than half AB. The two equal-radius circles meet above and below AB. Both intersection points are equidistant from A and B; their joining line is the perpendicular bisector. Subtracting the two distance-squared equations also gives x=0 in the symmetric coordinates shown.

A detail that matters

The compass opening must stay the same for both circles.

Keep the connection going

One idea leads to another.

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